#include 
     
      #include 
      
       #define M 1*10^6+10char str[M];/* 十进制变为二十六进制 */void solve_10_to_26(char str[]){    char re[M];    int p = M - 1;    int r, c;    sscanf(str, "R%dC%d", &r, &c);    re[p--] = 0;    while(r)    {        re[p--] = r % 10 + '0';        r = r/10;    }    while(c)    {        re[p--] = (c-1) % 26 + 'A';        c = (c-1)/26;    }    printf("%s\n", &re[p+1]);}/* 二十六进制变为十进制 */void solve_26_to_10( char str[] ){    char cc[M];    int c = 0;    int r;    sscanf( str, "%[A-Z]%d", &cc, &r );    int len = strlen(cc);    int p = 0;    while(p < len)    {        c = c + cc[p++] - 'A' + 1;        c = c * 26;    }    c = c / 26;    printf("R%dC%d\n", r, c);}int main(){    int n;    scanf("%d", &n);    while(n--)    {        scanf("%s", &str);        int a, b;        if ( sscanf(str, "R%dC%d", &a, &b ) == 2)            solve_10_to_26(str);        else            solve_26_to_10(str);    }    return 0;}